In: Statistics and Probability
(Problem 6) In a popular day care center, the probability that a child will play with the computer is 0.45; the probability that he or she will play dress-up is 0.27; play with blocks, 0.18; and paint, 0.1. a) Construct the probability distribution for this discrete random variable.
b) What is the Probability a child plays with a computer or paint
(Problem 7) The county highway department recorded the following probabilities for the number of accidents per day on a certain freeway for one month. The number of accidents per day and their corresponding probabilities are shown. Find the mean, variance, and standard deviation.
Can you make sure I answered it correctly
Given:
Number of accidents X |
0 |
1 |
2 |
3 |
4 |
Probability P(X ) |
0.4 |
0.2 |
0.2 |
0.1 |
0.1 |
my answer |
x |
p(x) |
x*p(x) |
X^2 *P(x) |
0 |
0.4 |
0 |
0 |
1 |
0.2 |
0.2 |
0.008 |
2 |
0.2 |
0.4 |
0.016 |
3 |
0.1 |
0.3 |
0.003 |
4 |
0.1 |
0.4 |
0.004 |
total |
1 |
1.3 |
0.031 |
Mean: 1.3
Variance= -1.66
SD= 1.29
Problem 6:
(a)
Probability Distribution for the Discrete Random Varable:
Let:
x = 1 for computer
2 for dress - up
3 for blocks
4 for paint
Thus, we get tehe Discrete Probability Distribution as follows:
x | p(x) |
1 | 0.45 |
2 | 0.27 |
3 | 0.18 |
4 | 0.10 |
(b)
P(Computer OR Paint) = P(x = 1 OR 4) = (x= 1) + P(x=4) = 0.45+ 0.10 = 0.55
Problem 7:
x | p | xp | x2 p |
0 | 0.4 | 0 | 0 |
1 | 0.2 | 0.2 | 0.2 |
2 | 0.2 | 0.4 | 0.8 |
3 | 0.1 | 0.3 | 0.9 |
4 | 0.1 | 0.4 | 1.6 |
Total 1.3 3.5
Mean = E(x) = 1.3
E(X2) = 3.5
Variance = E(X2) - (E(X))2
= 3.5 - 1.32 = 1.81
Standard Deviation = = 1.3454