Question

1.

What is the mass of 6.0 x10^23 particles of C7H15O4

2.

how many moles of C8H14O4 does 137.0 mL contain? Density is 1.0 g/mL

Answer 1

Mole Chart

1 mole of any substance contains 6.02210²³ (Avagadro number) particles and the wight of 1 mole of a substance is known as molar weight.

Answer

1) What is the mass of 6.0 x10²³ particles of C7H15O4

1 mole of any substance contains 6.02210²³ particles

Number of moles in 6.0 x10^23 particles = Given the number of particle /Avagadro number

                                                             = 6.0 x10²³ / 6.02210²³

                                                                                 =1.0 mole

The Mass of 0.996 moles of C7H15O4     = Number of moles of substance x Molar mass of substnce

                                                             =1.0 moles x 163.19 g/mol

                                                             =163.19g

the mass of 6.0 x10²³ particles of C7H15O4=163.19g

2) How many moles of C8H14O4 does 137.0 mL contain? Density is 1.0 g/mL

Amount of C8H14O4 in the solution = Amount of solution x Density of the solution

                                                    =137.0 ml x 1.0g/ml

                                                    = 137.0 g

Number of moles of C8H14O4        = Givn mass of the subtance/ Molar mass of the subtance

                                                    =137.0g / 174.19 g/mol

                                                    =0.78 mols

Note