In: Chemistry
Given the skeletal drawing of several molecules ( organic chemistry style), how do you determine which molecule is the most acidic (e.g. how does resonance, inductive effect, separation of charge, negative/ positive charge, and other factors that I am not currently aware play a role?-- please state what those other unknown factors are). Conversely, how do you determine which molecule is the most basic given several molecules to compare. Consequently, what are the factors that determine which molecule is the most basic? Please please provide me an answer that goes beyond just stating the factors determining basicity or acidity. Please go to the extent of explaning how these factors help determine which molecule is the most basic or acidic, not just basic or acidic alone.
Here we have to look for certain functional groups first.
If carboxylic
group is present, the molecule is acidic. If phenolic
group is present, the molecule is acidic. But carboxylic acids are
more acidic than phenols.
In carboxylic acids, if electron withdrawing group is present,
then acidity increases. Thus, chloro acetic acid
is more acidic than acetic acid
due to presence of electron withdrawing chlorine atom. Similarly,
electron releasing groups decreases the acidity of carboxylic
acids. Thus, p-methoxy benzoic acid
is less acidic than benzoic acid
due to presence of electron releasing methoxy group.
If amino
group is present, the molecule is basic.In gas phase, with
increase in number of alkyl groups, the basicity of aliphatic
amines increases. Thus, decreasing order of basicity is trimethyl
amine > dimethyl amine> methyl amine > ammonia. In case of
substituted anilines, electron releasing groups (such as methoxy,
methyl, ammino) increase the basic strength whereas electron
withdrawing groups (such as nitro, cyano, carboxylic, halo)
decrease the base strength. Thus, 4-methoxy aniline is more basic
than aniline whereas 4-nitroaniline is less basic than aniline.