In: Chemistry
Write the reaction of the following weak base with water. (1 point each)
A. methyamine
B. pyridine
2. What is the pH of 0.055 M aniline? Construct and use an ICE table. Use appropriate assumption. Check assumptions and if an assumption is false redo the problem without the false assumption. (3 points)-
A. CH3NH2 + H2O(l) -------------------> CH3NH3^+ (aq) + OH^- (aq)
B. C5H5N + H2O(l) ------------------> C5H5NH^+ (aq) + OH^- (aq)
2. C6H5NH2 + H2O --------------> C6H5NH3^+ (aq) + OH^- (aq)
I 0.055 0 0
C -x +x +x
E 0.055-x +x +x
Kb = [C6H5NH3^+][OH^-]/ [C6H5NH2]
4.3*10^-10 = x*x/0.055-x
4.3*10^-10*(0.055-x) = x^2
x = 4.86*10^-6
[OH^-] = x = 4.86*10^-6M
POH = -log[OH^-]
= -log4.86*10^-6
= 5.3133
PH = 14-POH
= 14-5.3133 = 8.6867 >>>>answer