Question

In: Chemistry

The bottle of hydrogen peroxide you used in Experiment 1: Ideal Gas Law - Finding Percent H2O2 is labeled as a 3% solution (the same as store-bought hydrogen peroxide)

NEED ASSISTANCE TO CHECK MY WORK

The goal for Experiment 1: Ideal Gas Law - Finding Percent H2O2 with Yeast is to find the percentage of hydrogen peroxide in the solution. To determine percentage, you need to first determine how many moles of hydrogen peroxide are present. Rearrange PV=nRT to solve for n, then plug in your known values for P, V, R, and T. Show your rearrangement of the ideal gas law equation from Experiment 1 to solve for n. Then plug in your P, V, R, and T values (using proper units) and solve. NOTE: All work must be shown.

Show your calculations from Experiment 1: Ideal Gas Law - Finding Percent H2O2 with Yeast for determining the theoretical number of moles of O2 if the hydrogen peroxide were a 100% solution. NOTE: All work must be shown.

Using the actual moles of O2 you determined from your experiment (n) and the theoretical moles of O2 you just calculated, show your calculations from Experiment 1: Ideal Gas Law - Finding Percent H2O2 with Yeast for determining the percent hydrogen peroxide in your experimental sample. NOTE: All work must be shown.

The bottle of hydrogen peroxide you used in Experiment 1: Ideal Gas Law - Finding Percent H2O2 is labeled as a 3% solution (the same as store-bought hydrogen peroxide). Do your experimental results support this (with consideration given to experimental error)? Show your calculations for your percent error of your results. NOTE: All work must be shown.

P= .998 atm

V= 50ml

R= (constant) 0.0821

T= 293 Kelvin

5ML of 3% H2O2 were used.

Solutions

Expert Solution

P = 0.998 atm ; V = 50 mL = 0.05 L ; R= (constant) 0.0821 Latm/molK ; T= 293 Kelvin

Now, PV = nRT

Here, = Actual moles of O2

Now, Theoretical moles of O2 = H2O2 used * H2O2 density *

= 5mL * 1.02g/mL * = 0.075 moles O2

Now, % H2O2 =

= =Actual percent of H2O2

Given, Theoretical percent of H2O2 = 3%

Percent error = %


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