Question

In: Chemistry

A 3.0% by mass aqueous solution of hydrogen peroxide (H2O2) can be purchased at a pharmacy;...

A 3.0% by mass aqueous solution of hydrogen peroxide (H2O2) can be purchased at a pharmacy; by contrast, chemistry departments can purchase 30.0% by mass aqueous solution of hydrogen peroxide having a density of 1.10 g/mL at 25°C.

How many moles of hydrogen peroxide are supplied by 2.00 g of the 30.0% solution at 25°C?

How many moles of hydrogen peroxide are supplied by 2.00 mL of the 30.0% solution at 25°C.

What mass in grams of water is present in 2.00 mL of the 30.0% solution at 25°C?

How many hydrogen peroxide molecules are present per milliliter of the 30.0% solution at 25°C?

Solutions

Expert Solution


How many moles of hydrogen peroxide are supplied by 2.00 mL of the 30.0% solution at 25°C.

solution :

mass of solution = v*d

                 = 2*1.1 = 2.2 g

so that ,

mass of H2O2 in 2.2 g solution = 2.2*30/100 = 0.66 g

no of mol of H2O2 = w/w = 0.66/34 = 0.0194 mole


What mass in grams of water is present in 2.00 mL of the 30.0% solution at 25°C?

solution :

mass of solution = v*d

                 = 2*1.1 = 2.2 g

so that ,

mass of H2O2 in 2.2 g solution = 2.2*30/100 = 0.66 g

mass of water in solution = 2.2-0.66 = 1.54 g

How many hydrogen peroxide molecules are present per milliliter of the 30.0% solution at 25°C?

solution :

mass of solution = v*d

                 = 1*1.1 = 1.1 g

so that ,

mass of H2O2 in 1.1 g solution = 1.1*30/100 = 0.33 g

no of mol of H2O2 = 0.33/34 = 0.0097 mole

no of molecules of H2O2 = 0.0097*6.023*10^23

               = 5.84*10^21 molecule


Related Solutions

•A 25.00 mL volume of commercial hydrogen peroxide (H2O2) solution was diluted to 250.0 mL in...
•A 25.00 mL volume of commercial hydrogen peroxide (H2O2) solution was diluted to 250.0 mL in a volumetric flask. Then 25.00 mL of the diluted solution were mixed with 200 mL of water and 20 mL of H2SO4 and titrated with 0.02123 M KMnO4. The first pink color was observed with 27.66 mL of titrant. A blank prepared from water in place of H2O2 required 0.04 mL to give visible pink color. Find the molarity of the commercial H2O2.
The bottle of hydrogen peroxide you used in Experiment 1: Ideal Gas Law - Finding Percent H2O2 is labeled as a 3% solution (the same as store-bought hydrogen peroxide)
NEED ASSISTANCE TO CHECK MY WORK The goal for Experiment 1: Ideal Gas Law - Finding Percent H2O2 with Yeast is to find the percentage of hydrogen peroxide in the solution. To determine percentage, you need to first determine how many moles of hydrogen peroxide are present. Rearrange PV=nRT to solve for n, then plug in your known values for P, V, R, and T. Show your rearrangement of the ideal gas law equation from Experiment 1 to solve for...
Sumazrize The Experiment? Into steps Introduction The decomposition of hydrogen peroxide in aqueous solution proceeds very...
Sumazrize The Experiment? Into steps Introduction The decomposition of hydrogen peroxide in aqueous solution proceeds very slowly. A bottle of 3% hydrogen peroxide sitting on a grocery store shelf is stable for a long period of time. The decomposition takes place according to the reaction below. 2 H2O2(aq) → 2 H2O + O2(g) A number of catalysts can be used to speed up this reaction, including potassium iodide, manganese (IV) oxide, and catalase (an enzyme). If you conduct the catalyzed...
Consider the reaction between hydrogen peroxide and iron in acidic solution: H2O2 (aq)+ F e^2+ (aq)...
Consider the reaction between hydrogen peroxide and iron in acidic solution: H2O2 (aq)+ F e^2+ (aq) + H2O (l) 1. Balance the reaction in acidic solution. 2. Determine the standard potential for this reaction. 3. Determine the potential for this reaction if the concentrations of hydrogen peroxide, iron (II), and iron (III) are all 0.10 M and the solution is pH = 4
The decomposition of hydrogen peroxide is thought to occur in three steps: step 1: H2O2(g) →...
The decomposition of hydrogen peroxide is thought to occur in three steps: step 1: H2O2(g) → 2 OH(g) step 2: H2O2(g) + OH(g) → H2O(g) + HO2(g) step 3: HO2(g) + OH(g) → H2O(g) + O2(g) a- Write the overall reaction: b- List any intermediates and/or catalysts and label which one they are c- What is the molecularity of each step? d- If the rate law is first order with respect to H2O2, which step is the rate-determining step? When...
Consider the decomposition of liquid hydrogen peroxide (H2O2) to form water and oxygen. Part A What...
Consider the decomposition of liquid hydrogen peroxide (H2O2) to form water and oxygen. Part A What is the heat of formation for hydrogen peroxide? Express your answer in to four significant figures. Part B What is the heat of formation for liquid water? Express your answer in to four significant figures. Part C What is the heat of formation for gaseous oxygen? Express your answer as an integer. Part D Write the balanced chemical equation that corresponds to the ΔH...
How many grams of hydrogen peroxide (H2O2) are needed to form 32.8 grams of oxygen gas?...
How many grams of hydrogen peroxide (H2O2) are needed to form 32.8 grams of oxygen gas? hydrogen peroxide (H2O2)(aq) ---> water(ℓ) + oxygen(g)
The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq) ---->H2O(l) + ½...
The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq) ---->H2O(l) + ½ O2(g) is first order in H2O2 with a rate constant of 1.10×10-3 min-1. If the initial concentration of H2O2 is 5.68×10-2 M, the concentration of H2O2 will be  M after 1800 minhave passed.
Hydrogen peroxide, H2O2, decomposes to water and oxygen gas. What is the oxidation state (oxidation number)...
Hydrogen peroxide, H2O2, decomposes to water and oxygen gas. What is the oxidation state (oxidation number) for oxygen in hydrogen perioxide? +1 +2 -1 -2 0 What volume of 0.10 M CH3CO2H is required to react with 0.50 moles of NaHCO3 in the following reaction? The balanced equation is: CH3CO2H(aq) + NaHCO3(s)  → CO2(g) + H2O(l) + NaCH3CO2(aq) 1.0 L 2.0 L 0.50 L 5.0 L 0.20 L If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL...
Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to...
Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to the reaction$$ \mathrm{BaO}_{2}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \longrightarrow \mathrm{BaSO}_{4}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) $$How many milliliters of \(3.00 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) (aq) are needed to react completely with \(47.9 \mathrm{~g} \mathrm{BaO}_{2}(\mathrm{~s}) ?\)Zinc reacts with hydrochloric acid according to the reaction equation$$ \mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{ZnCl}_{2}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g}) $$How many milliliters of \(4.00 \mathrm{M} \mathrm{HCl}(\mathrm{aq})\) are required to react with \(4.55 \mathrm{~g} \mathrm{Zn}(\mathrm{s}) ?\)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT