The system: 2A + B ↔ 2C ; initially started with 1 mole of B and...

The system: 2A + B ↔ 2C ; initially started with 1 mole of B and 1 mol A in a 1L flask. Keq = 6.8 x 10-5 To calculate the equilibrium concentrations a simplifying assumption (approximation) can be made.

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Expert Solution

2A + B ↔ 2C

I 1 1 0

C -2x -x 2x

E 1-2x 1-x 2x

Ka = [C]^2/[A]^2[B]

6.8*10^-5 = (2x)^2/(1-2x)(1-x)

6.8*10^-5 *(1-2x)(1-x) = 4x^2

x = 0.0041

[A] = 1-2x = 1-2*0.0041 = 0.9918M

[B] = 1-x = 1-0.0041 = 0.9959 M

True >>>>answer

queen_honey_blossom answered 2 years ago

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The system: 2A + B ↔ 2C ; initially started with 1 mole of B and...

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