Question

For the reaction 2A(g)⇌B(g)+2C(g), a reaction vessel initially contains only A at a pressure of PA=240 mmHg. At equilibrium, PA=41 mmHg.

Answer 1

                  2A(g)    ⇌    B(g )    +   2C(g)

   I               240              0               0

   C            -2*99.5         99.5         2*99.5

   E             41                99.5         199

          At equilibrium PA = 41mmHg

                                 PB     = 99.5mmHg

                                 Pc    = 199mmHg

           Kp   = PB*P^2C/P^2A

                    = 99.5*(199)^2/(41)^2

                    = 2344   or 2.344*10^3 >>>>answer