In: Chemistry
For the reaction 2A(g)⇌B(g)+2C(g), a reaction vessel initially contains only A at a pressure of PA=270 mmHg . At equilibrium, PA=55 mmHg .
2A(g) ⇌ B(g) + 2C(g),
I 270 0 0
C -2x x 2x
E 270-2x x 2x
PA = 270-2x = 55
x = 107.5
PB = x = 107.5 mmHg
PC = 2x = 2*1.07.5 = 215mmHg
Kp = PB* P^2C/P^2A
= 107.5 * (215)^2/(55)^2 = 1642.7 >>>answer