In: Chemistry
What is the amount of energy emitted in KJ from a
photon given off by a sulfur atom with a wavelength of 702.3
nm?
Given
Wavelength of Photon = 702.3 nm
We have relation, 1 nm = 10 -09 m
Wavelength
of Photon = 702.3 nm
( 10 -09 m / 1 nm
)
Wavelength of photon =
7.023
10 -07
m
We have,
Energy = h C /
Where, h
is a planck constant , C is velocity of light and
is
wavelength of light.
Energy of
photon = ( 6.626
10 - 34
J . s ) ( 3.00
10 8
m /s ) / 7.023
10 -07
m
Energy
of photon = 2.830
10 - 19
J = 2.830
10 - 22
k J
ANSWER : Amount of energy emitted from a photon
given off by a S atom is 2.830
10 - 22
k J