In: Chemistry
What is the amount of energy emitted in KJ from a
photon given off by a sulfur atom with a wavelength of 702.3
nm?
Given
Wavelength of Photon = 702.3 nm
We have relation, 1 nm = 10 -09 m
Wavelength of Photon = 702.3 nm ( 10 -09 m / 1 nm )
Wavelength of photon = 7.023 10 -07 m
We have, Energy = h C /
Where, h is a planck constant , C is velocity of light and is wavelength of light.
Energy of photon = ( 6.626 10 - 34 J . s ) ( 3.00 10 8 m /s ) / 7.023 10 -07 m
Energy of photon = 2.830 10 - 19 J = 2.830 10 - 22 k J
ANSWER : Amount of energy emitted from a photon given off by a S atom is 2.830 10 - 22 k J