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Calculate the energy (J) of the photon emitted when an electron in the hydrogen atom falls...

Calculate the energy (J) of the photon emitted when an electron in the hydrogen atom falls from n=5 to n=2 .
Use 2.178 x 10-18 J for the constant in the Bohr equation.

Answer should be in scientific notation, e.g.
3000 = 3E3

I have no idea how to get this problem help me!!

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Expert Solution

queen_honey_blossom answered 2 years ago
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