Question

what is the molarity of a KOH solution if 24.6 ml neutralizes 44.0 mL of a 0.211 M HCI?

Answer 1

The neutralization reaction involves here :

                   KOH + HCl      KCl + H₂O

Given that molarity of HCl is 0.211M that means molarity of H⁺ ions in HCl is 0.211M as well.we will find out the no.of moles of H⁺ ions by the formula :

molarity = no. of moles / volume in L

no.of moles of H⁺ ions = 0.211 M x 0.0440 L

                                    = 0.0093 moles

As it's a neutralization reaction so the 0.0093 moles of H⁺ ions will neutralize 0.0093 moles of OH^- ions of KOH.

So the molarity of KOH solution = 0.0093moles / 0.0246L

                                                  = 0.378 M