In: Chemistry
what is the molarity of a HCl solution if a 10.0 mL sample is neutralized by a 44.3 mL of a 0.111 molar solution of Ba(OH)2
Ba(OH)2(aq) + 2HCl(aq) -----------------> BaCl2(aq) + 2H2O(l)
1mole 2 moles
HCl Ba(OH)2
M1 = M2 = 0.111M
V1 = 10ml V2 = 44.3ml
n1 = 2 n2 = 1
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.111*44.3*2/10*1
= 0.983M
The molarity of HCl is 0.983M