In: Chemistry
What is the molality and molarity of solution prepared by dissolving 35.0 mL of benzene (density = 0.877 g/mL) in 175 mL of hexane (density = 0.660 g/mL)? Assume volumes are additive.
volume of benzene = 35 mL
mass of benzene = volume x density
= 35 x 0.877
= 30.695 g
moles of benzene = mass / molar mass = 30.695 / 78.11 = 0.393
mass of hexane = 175 x 0.660 = 115.5 g = 0.1155 kg
volume of hexane = 175 mL = 0.175 L
molality = moles of solute / mass of solvent in kg
= 0.393 / 0.1155
= 3.4 m
molality = 3.4 m
molarity = moles / volume of solution
= 0.393 / (0.035 + 0.175)
= 1.87 M
Molarity = 1.87 M