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In: Chemistry

What is the molality and molarity of solution prepared by dissolving 35.0 mL of benzene (density...

What is the molality and molarity of solution prepared by dissolving 35.0 mL of benzene (density = 0.877 g/mL) in 175 mL of hexane (density = 0.660 g/mL)? Assume volumes are additive.

Solutions

Expert Solution

volume of benzene = 35 mL

mass of benzene = volume x density

                             = 35 x 0.877

                             = 30.695 g

moles of benzene = mass / molar mass = 30.695 / 78.11 = 0.393

mass of hexane = 175 x 0.660 = 115.5 g = 0.1155 kg

volume of hexane = 175 mL = 0.175 L

molality = moles of solute / mass of solvent in kg

             = 0.393 / 0.1155

             = 3.4 m

molality = 3.4 m

molarity = moles / volume of solution

              = 0.393 / (0.035 + 0.175)

              = 1.87 M

Molarity = 1.87 M


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