Question

In: Biology

Is everyone's paternal gene silenced because of imprinting in that section of chromosome 15 that causes...

Is everyone's paternal gene silenced because of imprinting in that section of chromosome 15 that causes angelman syndrome? (when the other parents gene is silenced and now there is no back up because of imprinting caused by methylation) I'm asking if every typical person has this imprinting for angelman syndrome and vice versa maternally for Prader-willie syndrome I'm getting confused while writing a report.
(I need help as soon as possible because I'm writing a report for tomorrow). Thank you! I give thumbs up.

Solutions

Expert Solution

To answer your first of all lets understand what is genomic imprinting

When an embryo is formed by fusion of male and female nucleus than all the genes from sperm nucleus and egg nucleus is not functionally equivalent.Some of gene of maternal side and some of paternal side are activated other genes are inactivated or silenced by methylation in cytosine residue ofDNA so basically genomic imprinting is Inactivation of gene

In everyone pair of chromosome present in which half chromosome comes from paternal father side and half chromosome comes from mother maternal side.so basically every child has two copy of single gene but not both copy are functional one copy either from paternal side or maternal side is Inactivated by methylation in cytosine residue as we have discussed above its called genomic imprinting

Hence for Normal development of embryo single copy of every gene is normal and other is inactivated or silenced

Now coming to the question Prader wili and angelmon syndrome is caused due to some deletion or mutation in the region of chromosome 15

As you know due to genomic imprinting some gene of chromosome15 of paternal side will be activated and other will inactivated silenced in the same way some gene of maternal side chromosome 15 will be activated and other inactivated or silenced

Genes of maternal side which is activated is silenced in paternal side and vice-versa for maternal side hence only one copy of single funtional gene is present

In chromosome 15 some gene are activated from paternal side and maternal side gene are inactivated silenced by imprinting but when there is deletion or mutation on region of paternal side chromosome 15 than genes of that area will not be expressed and causes Prader willi syndrome in which child has small stature ,small hand and feet and is mentally retarded.

In the same way some genes is activated on maternal side chromosome 15 and paternal side genes on chromosome 15 is inactivated silenced so if there is deletion or mutation of that specific genes on maternal side chromosome 15 than it will cause Angelman syndrome in which there is uncontrolled muscle movement, feeding issues and frequent laughter ( Always smile).

In both cases other copy of paternal or maternal side chromosome is normal but as it is turned off by imprinting so it cannot fill the gaps hence the presence of a second good copy of the gene on the methylated, tightly packed copy of chromosome 15 is of no use in correcting the defect.

So your query that everyone's paternal gene silenced because of imprinting in that section of chromosome 15 that causes angelman syndrome and vice-versa for prader-willi syndrome

Yes it is true In prader willi syndrome and angelman syndrome one copy of gene of paternal side or maternal side is defected but other copy of maternal side or paternal is Normal but they are silenced due to imprinting that is methylation on cytosine residue of DNA and it cannot be activated

Hence In every person that paternal gene section of chromosome 15 that causes angelman syndrome is silenced due to imprinting and vice-versa for prader-willi syndrome

Plz upvote my answer Thank you?


Related Solutions

A male with gigantism (due to paternal duplication of the Igf2 locus on the same chromosome)...
A male with gigantism (due to paternal duplication of the Igf2 locus on the same chromosome) married a normal individual. He worries about having children since they may also have gigantism. What would you tell him? Question 2 options: They will be all healthy. Only sons have 50% chance of developing gigantism. Children have 50% chance of having gigantism. Only daughters have 50% chance of developing gigantism.
if there is a deletion in the imprinting control region (ICR) of a gene in the...
if there is a deletion in the imprinting control region (ICR) of a gene in the parent chromosome, will that be passed on to the offspring? This has me confused because, I know that in blastocyst, the chromosomes get de-methylated and re-methylated.
This is normally accomplished through methylation of a cytosine: a. paternal effect   b. imprinting   c. epistasis   d. maternal inheritance   e....
This is normally accomplished through methylation of a cytosine: a. paternal effect   b. imprinting   c. epistasis   d. maternal inheritance   e. aromatase
In a heterozygous diploid cell in which gene B is on chromosome one, gene G is...
In a heterozygous diploid cell in which gene B is on chromosome one, gene G is on chromosome two, and the cell contains alleles B ,b and G, g. a. Draw and label the cell at Metaphase and Anaphase and at the end of Mitosis. Label each chromatid. Label the ploidy of each cell. b. Draw and label the cells as to show the chromosomes lined up in the cell(s) at Metaphase of in Meiosis I and Meiosis II and...
Question text In drosophila (fruit flies): The yellow gene is on the X-chromosome, the gene product...
Question text In drosophila (fruit flies): The yellow gene is on the X-chromosome, the gene product plays a role in body colour. Wild type flies are a light brown/tan in colour, homozygote yellow mutants have a more yellow shaded body colour. We'll use y+ to represent the wild type allele, and y to represent the mutant allele. y+ is dominant to y. The vestigial gene is on chromosome 2. Homozygote vestigial mutants have very short wings, and cannot fly. We'll...
What method can be used to identify the location of a gene on a chromosome? A....
What method can be used to identify the location of a gene on a chromosome? A. Fluorescent in situ hybridization (FISH) B. Fluorescent Immunohistochemistry (IHC) C. DNA fingerprinting D. Polymerase chain reaction (PCR)
Imagine that the P gene lies on the Z chromosome, and controls the brightness of a...
Imagine that the P gene lies on the Z chromosome, and controls the brightness of a bird’s plumage. The dominant wild-type Zpb allele produces bright plumage, while the recessive variant Zpd allele produces dull plumage. If you cross a pure-breeding bright male with a dull female, what proportion of genotypes/phenotypes do you expect to see in the F1 generation? If a male and female from the F1 generation mate, what genotypes/phenotypes do you expect to see in the F2 generation?...
Suppose gene A is on the X chromosome, and genes B, C and D are on...
Suppose gene A is on the X chromosome, and genes B, C and D are on three different autosomes. Thus, A- signifies the dominant phenotype in the male or female. An equal situation holds for B-, C- and D-. The cross AA BB CC DD (female) x aY bb cc dd (male) is made. A) probability of obtaining A- individual in F1 B) probability of obtaining an a male in the F1 progeny C) Probability of A- B- C- D-...
7. Briefly describe how inheritance of methylation patterns by offspring (gene imprinting) is different from the...
7. Briefly describe how inheritance of methylation patterns by offspring (gene imprinting) is different from the inheritance of methylation patterns for daughter cells.
In a genetics experiment of a pathway, loss of function in gene X or gene Y causes a blue phenotype, and loss of function in gene Z causes a green phenotype.
The idea is about genetic testing not about getting a specific answer. In a genetics experiment of a pathway, loss of function in gene X or gene Y causes a blue phenotype, and loss of function in gene Z causes a green phenotype. What experiments could you use to find the order and regulatory relationships of all the genes? Assume you have all the types of alleles you would want and explain what you would observe in your experiment if...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT