In: Chemistry
A. Calculate the pH of a solution formed by combining 0.125 mL
of 0.55 M HI with 0.400 mL of 0.14 M KOH at
25°C.
B. Calculate the pH of a solution formed by combining 0.125 mL of
0.55 M HI with 0.400 mL of 0.18 M KOH at
25°C.
C. A 50.00-mL sample of 0.0750 M HCN was titrated with
0.3995 M NaOH. What is the pH of the resulting solution
after 5.00 mL of NaOH were added at 25°C? Ka for HCN is
6.2x10–10 at 25°C.
D. A 50.00-mL sample of 0.225 M HCO2H was
titrated with 0.1125 M NaOH. What is the pH at the
equivalence point at 25°C? Ka for
HCO2H is 1.8x10–4 at 25°C.
E. A 25.00-mL sample of 0.225 M HNO2 was
titrated with 0.1111 M NaOH. What is the pH at the
equivalence point at 25°C? Ka for HNO2 is
7.2x10–4 at 25°C.
F. A solution of 0.600 g of diprotic acid in 100.0 mL of water was
titrated with 0.300 M NaOH to the second equivalence point. The
volume of the base used was 34.5 mL. What is the molar mass of acid
in g/mol?
G. The solubility of Gd2(SO4)3 is
4.0 g/100 mL. What is the Ksp?
H. What is the molarity of Ba2+ in a saturated solution
of Ba3(AsO4)2? (Ksp = 1.1 x
10-13)
I. What is the concentration of Mg2+ when
MgF2 (Ksp = 6.4 x 10-9) begins to precipitate
from a solution that is 0.20 M F-?
J. What is the pH of a saturated solution of Pb(OH)2
(Ksp = 1.2 x 10-5)?
please answer showing steps ( A to J )
A)
millimoles of HI = 0.125 x 0.55 = 0.06875
millimoles of KOH = 0.400 x 0.14 = 0.056
[H+] = 0.06875 - 0.056 / (0.125 + 0.400) = 0.0243 M
pH = -log (0.0243)
pH = 1.62
B)
[OH-] = 0.400 x 0.18 - (0.125 x 0.55) / 0.125 + 0.400
= 0.00619 M
pOH = -log (0.00619) = 2.208
pH = 11.79
C.
mmoles of HCN = 50 x 0.0750 = 3.75
mmoles of NaOH = 5 x 0.3995 = 1.9975
HCN + NaOH ---------------> CN- + H2O
3.75 1.9975 0 0
1.75 0 1.9975
pH = pKa + log [salt / acid]
= 9.21 + log [1.9975 / 1.75]
pH = 9.26
D.
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (3.74 + log 0.075)
pH = 8.31