Assume for the moment that air consists of 80.00% nitrogen (N2) and 20.00% oxygen (O2) by...

Assume for the moment that air consists of 80.00% nitrogen (N2) and 20.00% oxygen (O2) by volume. Use these figures and typical values for temperature and pressure (1.000atm and 25.00°C) to calculate the density of air in g/L.

Expert Solution

Answer – We are given, percent of N₂ in air = 80.00 %

For O₂ = 20.00 % , P = 1.00 atm , T = 25 +273 = 298 K

We need to calculate the mass of N₂ and O₂

mass of N₂ = 28.014*80.0 % / 100 %

= 22.41 g

Mass of O₂ = 31.998 g * 20.0 % / 100 %

= 6.399 g

So total mass of air = 22.41 +6.399

= 28.81 g

We know formula for calculating the density

Density = PM/RT

= 1.00 atm * 28.81 g / 0.0821 atm.L.mol^-1.K^-1 * 298 K

= 1.18 g/L

The density of air is 1.18 g/L

queen_honey_blossom answered 1 year ago

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