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Write a reaction for the dissolution of fluorite (CaF2) in water. Calculate the change in enthalpy,...

Write a reaction for the dissolution of fluorite (CaF2) in water. Calculate the change in enthalpy, entropy and free energy for this reaction at 25°C

Solutions

Expert Solution

Dissolution of CaF2 is

CaF2(s) + H2O(l) ------------------- CaF2(aq)

Chnage in enthalpy = H= Hf of CaF2(aq) - [Hf of CaF2(s) + Hf of H2O]

                                     =-1184.07 -[-1219.64 -285.83]

H= 321.4 KJ

Change in entropy =S= Sf of CaF2(aq) - [ Sf of CaF2(s) + Sf of H2O]

                                           = 92.59 -[68.87+69.91]

S = -46.19J

G = H - T S                      T= 25C = 25+273 = 298K

G = 321.4KJ - [298x(-46.19J)]

G = 335.164KJ

G = 335.16KJ.

queen_honey_blossom answered 2 years ago
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