In: Electrical Engineering
QUESTION 2
Suppose you are creating a truth table with 3 inputs (a, b, and c) and 1 output (F). If an 'x' symbol indicates "don't care" (the value of the input does not effect the output), how many input combinations are covered by the single row of a truth table shown below?
a | b | c | F |
---|---|---|---|
x | 1 | x | 1 |
- |
1 |
|
- |
2 |
|
- |
3 |
|
- |
4 |
|
- |
None of the above |
QUESTION 3
Suppose you have a 4x1 multiplexer (MUX) whose inputs are shown below in a single row of a truth table. The inputs i0 - i3 are data inputs and s0 and s1 are selector bits. What Boolean value will the data output, d, be for this row?
i3 | i2 | i1 | i0 | s1 | s0 | d |
---|---|---|---|---|---|---|
1 | 1 | 0 | 1 | 0 | 1 | ? |
- |
0 |
|
- |
1 |
|
- |
2 |
|
- |
3 |
QUESTION 4
Suppose you have a 4x1 multiplexer (MUX) whose inputs are shown below in a single row of a truth table. The inputs i0 - i3 are data inputs and s0 and s1 are selector bits. What Boolean value will the data output, d, be for this row?
i3 | i2 | i1 | i0 | s1 | s0 | d |
---|---|---|---|---|---|---|
1 | 1 | 0 | 1 | 0 | 0 | ? |
- |
0 |
|
- |
1 |
|
- |
2 |
|
- |
3 |
QUESTION 5
Suppose you have a 4x1 multiplexer (MUX) whose inputs are shown below in a single row of a truth table. The inputs i0 - i3 are data inputs and s0 and s1 are selector bits. What Boolean value will the data output, d, be for this row?
i3 | i2 | i1 | i0 | s1 | s0 | d |
---|---|---|---|---|---|---|
0 | 0 | 0 | 1 | 1 | 0 | ? |
- |
0 |
|
- |
1 |
|
- |
2 |
|
- |
3 |
QUESTION 6
Suppose you have a 4x1 multiplexer (MUX) whose inputs are shown below in a single row of a truth table. The inputs i0 - i3 are data inputs and s0 and s1 are selector bits. What Boolean value will the data output, d, be for this row?
i3 | i2 | i1 | i0 | s1 | s0 | d |
---|---|---|---|---|---|---|
0 | 1 | 1 | 1 | 1 | 1 | ? |
- |
0 |
|
- |
1 |
|
- |
2 |
|
- |
3 |
QUESTION 7
Suppose you have a 4x2 priority encoder whose inputs are shown below in a single row of a truth table. The inputs d3 - d0 are inputs and e1 and e0 are output bits. What value will the data outputs, e1 and e0, be for this row (assume d3 is the highest priority input and results in the largest encoded value)?
d3 | d2 | d1 | d0 |
---|---|---|---|
0 | 1 | 1 | 1 |
- |
|
|||||
- |
|
|||||
- |
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|||||
- |
|
QUESTION 8
Suppose you have a 4x2 priority encoder whose inputs are shown below in a single row of a truth table. The inputs d3 - d0 are inputs and e1 and e0 are output bits. What value will the data outputs, e1 and e0, be for this row (assume d3 is the highest priority input and results in the largest encoded value)?
d3 | d2 | d1 | d0 |
---|---|---|---|
0 | 0 | 0 | 1 |
- |
|
|||||
- |
|
|||||
- |
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|||||
- |
|
QUESTION 9
Select all of the minterms that will be in the Boolean equation that describes the output, f, in the following truth table (a, b, and c are inputs).
a | b | c | f |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
- |
a'b'c' |
|
- |
a'b'c |
|
- |
a'bc' |
|
- |
a'bc |
|
- |
ab'c' |
|
- |
ab'c |
|
- |
abc' |
|
- |
abc |
The solutions is given below:
2. In the question given, x indicate don't care condition. The required table have been constructed below:
a | b | c | F |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 1 |
1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 |
Therefore, with the single row given in the question, actually 4 different combinations are possible.
3. In a 4X1 multiplexer, there are 4 input lines (i3 to i0) and 2 select lines (s1 and s0). There is only one output line d.
Now, if s1s0=00, then d=i0
s1s0=01, then d=i1
s1s0=10, then d=i2
s1s0=11, then d=i3
According to the given question, s1s0=01. Therefore the inout coming from line i1 will be found at the output. Therefore the binary value of output d will be d=0.
4.
In a 4X1 multiplexer, there are 4 input lines (i3 to i0) and 2 select lines (s1 and s0). There is only one output line d.
Now, if s1s0=00, then d=i0
s1s0=01, then d=i1
s1s0=10, then d=i2
s1s0=11, then d=i3
According to the given question, s1s0=00. Therefore the inout coming from line i0 will be found at the output. Therefore the binary value of output d will be d=1.
5.
In a 4X1 multiplexer, there are 4 input lines (i3 to i0) and 2 select lines (s1 and s0). There is only one output line d.
Now, if s1s0=00, then d=i0
s1s0=01, then d=i1
s1s0=10, then d=i2
s1s0=11, then d=i3
According to the given question, s1s0=10. Therefore the inout coming from line i1 will be found at the output. Therefore the binary value of output d will be d=0.
As per the guideline, first 4 questions are solved and given above.
Hope this detailed explanation helps.