In: Chemistry
determine how many grams of N2 are produced from the reaction of 9.70 g of H2O2 and 5.08 g of N2H4.
2H2O+N2H4= 4H2O+N2
2 H2O2 + N2H4 ------------------> 4 H2O + N2
68.03 g 32.045 72.06 28 g
9.70 g 5.08 g ??
here limiting reagent is H2O2.
so the product formed based on limiting reagent.
68.03 g H2O2 ----------------> 28 g N2
9.70 g H2O2 -----------------> ??
mass of N2 formed = 9.70 x 28 / 68.03 = 3.99 g
mass of N2 formed = 3.99 g