In: Electrical Engineering
Given data:
Total volume: 133.7 ft^3
now, the tank to be constructed must be of cylinder with two hemispherical ends
let 'r' be the radius of the cylinder and the hemispere
'd' be the daimeter
according to the condition total length =2d
volume of the new tank = 2(volume of hemisphere) + volume of the cylinder
volume of hemisphere = 2/3 *pi* r^3
volume of cylinder= pi*r^2* l [here height= length]
as l= 2d= 2*2r=4r
volume of the new tank= 2(2/3 *pi*r^3) + (pi* r^2 *4r)
=4/3 * pi* r^3 + 4 pi * r^3
=4 * pi * r^3( 1/3 + 1)
=16/3 * pi * r^3
now total volume = new tank volume
133.7= 16/3 * pi * r^3
[ here pi =22/7 ]
r^3=7.97642
r = 1.99 feet
therefore radius r= 1.99 feet
length= 2d= 4r= 7.96
volume of the steel required= surface area of the tank * width of the wall
given that width of the wall = 1/4 feet
total surface area of the tank = 2( surface area of the hemisphere ) + surface area of the cylinder with open lids
=2 ( 2 * pi * r^2) + 2 * pi * r* l
= 4 * pi * r^2 + 8* pi * r^2 [ since l=4r]
= 12* pi * r^2
=12* 22/7 * (1.99)^2
=149.3523 feet^2
total steel required = thickness * surface area = 1/4 * 149.3523
=37.33809 feet^2