In: Statistics and Probability
1. Consider the following events for a college student being selected at random. A = student is a hockey player B = student is majoring in kinesiology. Translate the following phrase into symbols: The probability that the student is not a hockey player and is majoring in kinesiology.
Select one:
a. P(AcandB)
b. P(AandBc)
c. P(Bc|A)
d. P(A|Bc)
2. Suppose you roll two fair dice, one that is purple, and one other is violet. Each die can have numbers from 1 to 6. Determine the probability of getting a sum of 5, which means you add the number from each die together obtain the sum of 5.
Select one:
a. 4/36
b. 2/36
c. 5/36
d. 3/36
3. Suppose you have a jar that includes six balls, two gold balls, three purple balls, and one orange ball. You will draw the balls without replacement. Determine the probability of getting a gold ball on the first draw and a purple ball on the second draw. Note that the following probabilities are expressed in terms of products of non-reduced fractions.
Select one:
a. (2/6)(2/6)(2/6)(2/6)
b. (3/6)(3/6)(3/6)(3/6)
c. (2/6)(3/5)(2/6)(3/5)
d. (3/6)(2/5)
(1) P(Not playing Hockey) = 1 - P(playing Hockey) = P(Ac)
P(Student is majoring in kinesiology) = P(B)
The question is asking for the intersection value, and therefore Option a: P(Ac and B)
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(2) Probability = Favorable outcomes / Total Outcomes
We can get a sum of 5 in the following manner, assuming the first is the value on the purple and second is the value on violet. (4,1) (1,4) (2,3) and (3,2) = 4 possible Outcomes
Total outcomes = 62 = 36 (if you throw n dice, the total outcomes = 6n)
Therefore the required probability is Option a: 4 / 36
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(3) Total number of balls = 6
When picking without replacement, from the second pick onwards, the Total outcomes keep reducing by 1, as the first ball picked has not been replaced.
First Draw: P(Gold Ball) = 2 / 6
Second Draw: P(Purple Ball) = 3 / 5
Therefore the required probability is Option d: (3/6) * (2/5)
(It doesn't matter if the figures are changed in the options as the answer still remains the same (2/6) * (3/5) = 1/5 and (3/6) * (2/5) is also = 1/5)
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