Question

For the following reaction Kc = 2.20 ✕ 102 at 74°C. CO(g) + Cl2(g) ↔ COCl2(g) Find the equilibrium concentrations of all chemical species starting with [CO] = 0.105 M and [Cl2] = 0.105 M.

[CO] = M

[Cl2] = M

[COCl2] = M

Answer 1

for the reaction Co(g)+Cl2(g) ---->CoCl2(g)

[CO]=[Cl2]= 0.105 M

preparing ICE Table

component                  initial (M)            change (M)    equilibrium (M)

CO                               0.105                      -x                         0.105-x

Cl2                               0.105                      -x                        0.105-x

[CoCl2]                         0                             x                            x

Kc= [CoCl2]/[CO][Cl2]= x/(0.105-x)² = 2.2*100

when solved using excel, x= 0.0853 hence at equilibrium, [CO]=[Cl2]=0.105-0.0853= 0.0197M

[CoCl2]=0.0853M