Question

For the following reaction, Kc = 481 at 1000 K.

CO (g) + Cl2 (g) ↔ COCl2 (g)

If the reaction mixture initially contains a CO concentration of 0.2500 M and a Cl2 concentration of 0.185 M at 1000 K, what are the equilibrium concentrations of CO, Cl2, and COCl2 at 1000K

Answer 1

       CO (g) + Cl2 (g) ↔ COCl2 (g)

I 0.25          0.185           0

C - x    -x    +x

E   0.25-x        0.185-x         +x

    Kc     = [COCL2]/[CO][Cl2]

   481      = x/(0.25-x)(0.185-x)

481*(0.25-x)(0.185-x) = x

   x   = 0.179

[CO]   = 0.25-x = 0.25-0.179   = 0.071M

[Cl2]     = 0.185-x    = 0.185-0.179   = 0.006 M

[COCl2]   = x          = 0.179M