A 12% by mass solution of acetone (C3H6O) in water has a density of 0.9849 g/mL...

A 12% by mass solution of acetone (C3H6O) in water has a density of 0.9849 g/mL at 20˚C. What is the molality and molarity of this solution?

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Expert Solution

let volume = 1L = 1000ml

mass of solution = volume * density

= 1000*0.9849 = 984.9g

mass of acetone = 0.12*984.9 = 118.188g

no of moles of acetone = W/G.M.Wt

= 118.188/58 = 2.04moles

molarity = no of moles/volume of solution in L

= 2.04/1 = 2.04M

molality = M*1000/1000*d -M*gram molar mass

= 2.04*1000/1000*0.9849-2.04*58

= 2040/866.58 = 2.35m

queen_honey_blossom answered 1 year ago

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