Question

Acetone, the solvent in many nail polish removers, has a density of 0.791 g/mL. What is the volume, in mL, of 38.2 g of acetone?An automobile gasoline tank holds 31.0 gal when full. How many pounds of gasoline will it hold if the gasoline has a density of 0.737 g/mL?

Answer 1

Answer –

We are given, density of acetone = 0.791 g/mL, mass of acetone = 38.2 g

We need to calculate volume of the acetone and we know the formula

density = mass / volume

So, volume = mass / density

                   = 38.2 g / 0.791 g.mL^-1

                  = 48.29 mL of acetone

In the next problem we are given, volume of gasoline = 31.0 gal , density = 0.737 g.mL^-1

First we need to convert the given volume gal to mL

We know,

1 gal = 3785.41 mL

So, 31.0 gaql = ?

= 117348 mL

We know formula,

density = mass / volume

mass = density * volume

         = 0.737 g.mL^-1 * 117348 mL

         = 86485.3 g

Now we need to convert the mass g to pound (lb)

1 g = 0.002205 lb

86485.3 g = ?

= 191 lb