In: Physics
The values of resistors R1 and R2 is 33.803 Ohms and 40.736 Ohms, respectively. If a current 0.47799 Amps runs through R2, what is the potential difference across R1? Please include the correct SI units in the answer.
For a circuit with two resistors can be connected in two ways, (1) series connection and (2) parallel connection,
Lets see the first one (1) Series connection
The figure below shows a circuit with two resistors connected in series
For series connection, the current passing through will be same for both R1 and R2 ,and voltages will be V= VR1 + VR2
where V is the voltage source, VR1 is the voltage drop across resistor R1and VR2 is the voltage across resistor R2
Given that, I2 current through R2 is given as 0.47799 A , ie I2 = 0.47799 A, R1 = 33.803 ohms, R2 = 40.736 ohms.
Then,
Then,
From this it is clear that in a series connection Total voltage = VR1 + VR2
For parallel connection as shown in figure,
Current will be I = IR1 + IR2 , while voltage across the entire circuit will be always same.
Therefore, voltage across R1 is equal to the total voltage , ie V volt