let r1 and r2 be the relations represented as r1 (ABC) and r2 (ADE) .Assume the...

let r1 and r2 be the relations represented as r1 (ABC) and r2 (ADE) .Assume the corresponding domains of both the tables are same.r1 has 2000 tuples and r2 has 4500 tuples
1.common tuples between r1 and r2 are 500, what would be the resultant number of tuples for r1-r2, justify your answer
2.assuming 500 as the common tuples between r1 and r2,what is the maximum number of tuples that results in ]] A( r1) U ]] A r2. justify your answer.

Expert Solution

Answer

1) In this problem, between two relations different operation is performed (r1-r2). The difference operation in relation is the same as of set.

A-B={x | x ∈ A and x ∉ B}

This formula states that those elements in A but not in B.

So in this problem there are 500 common tuples.

relation r1 without 500 common tuple= 2000-500=1500

relation r2 without 500 common tuple=4500-500=400

so the result is r1-r2=1500

2) In the second part the operation is Union(U). The operation union in relation is the same as the set.

A-B={x | x ∈ A or x ∈ B}

The formula state that those elements present in either relation A or relation B. Also removing the repeated elements

The result of this problem is

A(r1) U A(r2)=2000+4000=6000

venereology answered 1 year ago

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