Question

In: Math

If three resistors with resistance of R1, R2, R3 are wired in parralle, their combined combined...

If three resistors with resistance of R1, R2, R3 are wired in parralle, their combined combined resitance R is given by the following formula:

1/R= 1/R1 + 1/R2 +1/R3

The design of a voltmeter requires that the resitance R2 be 80 ohms greater than the restance of R1, that the restance of R3 be 5 ohms greater than R1, and that their combined restance be 10 ohms. Find the value of each resistance.

R1=________ohms

R2=________ohms

R3=________ohms

Solutions

Expert Solution

If three resistors with resistance of R1, R2, R3 are wired in parallel, their combined resistance R is given by the following formula:

1/R= 1/R1 + 1/R2 +1/R3.

Since the resistance of R2 is 80 ohms greater than the resistance of R1, hence R2 = R1+80…(1). Also, since the resistance of R3 is 5 ohms greater than the resistance of R1, hence R3= R1+5…(2). Further, since the combined resistance of R1,R2 and R3 is 10 ohms, hence R = 10 so that 1/10 = (1/R1) +(1/R2) + (1/R3) or, 1/10 = (1/R1) + [1/(R1+80)]+ [1/( R1+5)] or, 1/10 = (3R12+170R1+400)/[R1(R1+5)(R1+80)] or, R1(R1+5)(R1+80) = 10(3R12+170R1+400) or, (R1)3+55(R1)2-1300R1- 4000 = 0 or, (R1-20) (R12 +75R1+200) = 0

A graph of (R1)2+75R1+200 is attached. It may be observed that this graph crosses the X-Axis/R1 at R1 =              -72.231 and R1 = -2.769. Further, since R1 cannot be negative, hence R1 = 20 ohms. Then R2 = 20+80 = 100 ohms and R3 = 20+5 = 25 ohms.

Note:

1. We can use the quadratic formula also on the equation (R1)2+75R1+200 to arrive at R1= -72.231 or,            R1 = -2.769.

2. The exact coordinates may be seen only in the original Desmos graph and not in an image thereof.


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