Let P(A) = 0.40, P(B) = 0.20, P(C) = 0.50, P(D) = 0.30, P(A ∩ B)...

Let P(A) = 0.40, P(B) = 0.20, P(C) = 0.50, P(D) = 0.30, P(A ∩ B) = 0.15, P(A | C) = 0.60, P(B | C) = 0.20, P(B ∩ D) = 0.10, and C and D are mutually exclusive.

Find ...

a. P(C ∩ D)

b. P(C U D)

c. P(B ∩ C)

d. Which one of the following pairs is a pair of statistically independent events? (A and C) (B and D) (B and C) (C and D)

Expert Solution

milcah answered 1 year ago

Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A)=0.30 and P(B) = 0.50

Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A)=0.30 and P(B) = 0.50. (a) Why is it not the case that P(A) + P(B) = 1? (b) Calculate P(A'). (c) Calculate P(A $ \cup $B). (d) Calculate P(A' $ \cap $B').

IMR 0.50 MMR 0.30 &

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