Question

In: Chemistry

What is the pH of the 25 mL of 0.200 M acetic acid when you add...

What is the pH of the 25 mL of 0.200 M acetic acid when you add 70 mL of 0.1M NaOH
pKa = 4.75

Solutions

Expert Solution

no of moles of CH3COOH   = molarity * volume in L

                                           = 0.2*0.025    = 0.005 moles

no of moles of NaOH           = molarity * volume in L

                                            =0.1*0.07   = 0.007 moles

no of mole of NaOH excess = 0.007-0.005   = 0.002 moles

total volume                 = 25+70   = 95ml = 0.095L

conc of NaOH       = no of moles/volume in L

                             = 0.002/0.095   = 0.021 M

NaOH --------> Na^+ (aq) + OH^- (aq)

0.021M                               0.021M

[OH^-]           =    [NaOH]

[OH^-]               = 0.021M

POH   = -log[OH^-]

           = -log0.021   = 1.6777

PH    = 14-POH

            = 14-1.6777    = 12.3223 >>>>answer


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