The chemical reaction involved in the oxidation of hydroquinone by hydrogen peroxide to produce quinone and...

The chemical reaction involved in the oxidation of hydroquinone by hydrogen peroxide to produce quinone and water is: C6H4 (OH)2 (aq) + H2O2 (aq) = C6H4O2 (aq) + 2 H20 (l). Calculate delta H for the above reaction from the following data. C6H4 (OH)2 (aq) = C6H4O2 (aq) + H2 (g) delta H = 177.4 kJ; H2(g) + O2 (g) = H2O2 (aq) delta H = -191.2 kJ; H2 (g) = 1/2 O2 (g) = H2O (g) delta H = -241.8 kJ; H2O (g) = H2O (l) delta H = -43.8 kJ. The enthapy for the oxidation of hydroquinone by hydrogen peroxide to produce water and quinone is _________kJ

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queen_honey_blossom answered 7 months ago

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