Question

In: Chemistry

Ammonia is produced by the catalytic reaction of nitrogen and hydrogen. A)   Write the chemical reaction...

Ammonia is produced by the catalytic reaction of nitrogen and hydrogen.

A)   Write the chemical reaction and balance it. Determine the stoichiometric coefficients.

B)    If 15 mol/sec of H2 is fed to the reactor, determine the amount of N2 required if a 20.% excess (of N2) is desired.

C)    If 5.0 mol/sec of H2 exits the catalytic reactor, determine:

i)   ξ.

ii)   the number of moles of all three components exiting the reactor.

iii)   the conversion of H2 and N2.

iv)   the exiting concentration of H2, N2, and ammonia.

D)   What are strategies to increase the conversion of H2?

Solutions

Expert Solution

a) Balanced Reaction

N2 + 3H2 -> 2NH3

b) Moles of N2 with excess

15 mol/s are fed of H2. By stoichiometry, we can determine how many theoretical moles of N2 we need:

15 mol/s of H2 * (1 mol of N2 / 3 moles of H2) = 5 mol/s of N2

5 mol/s of N2 * 1.2 = 6 mol/s of N2

c) Moles reacted 15 - 5 mol/s = 10 mol/s of H2

i) To get the extent of reaction, we divide it by stoichiometric coefficient:

10 mol/s of H2 / 3 = 3.3333 mol/s

Extent of reaction = 3.333 mol/s

ii) Moles exiting the reactor:

Moles of NH3 = 3.3333 * 2 = 6.6666 mol/s

Moles of H2 = 5 mol/s

Moles of N2 = 6 - 3.3333 = 2.6667 mol/s

iii) Conversion of H2= moles reacted / moles fed = 10/15 * 100= 66.667%

Conversion of N2= moles reacted / moles fed = 3.3333/6 * 100= 55.55%

iv) Exiting concentrations:

Total moles = 6.666 + 5 + 2.6667 = 14.3327

%N2 = 2.6667/14.3327 * 100 = 18.6%

%H2 = 5/14.3327 * 100 = 34.885%

%NH3 = 6.666 / 14.3327 * 100 = 46.51%

d) Strategies to increase conversion:

Apply le chatelier principle to shift equilibrium. One of the measures that could be taken is to add more reactants to shift equilibrium to the right. Also, pressure could be increased to reduce volume and so make the reaction produce more ammonia. Finally, temperature should be managed so that equilibrium could be shifted to the right and a good constant is obtianed as well.


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