A 45.00 mL mixture containing 0.0616 M Mn2 and 0.0616 M Pb2 is titrated with 0.0829...

A 45.00 mL mixture containing 0.0616 M Mn2 and 0.0616 M Pb2 is titrated with 0.0829 M K2S resulting in the formation of the precipitates MnS and PbS. Calculate pS2– at the following points in the titration. The Ksp values for MnS and PbS are 4.6 × 10-14 and 8.9 × 10-29, respectively.

17.2 mL -- ?

45.5 mL -- ?

The second equivalence point -- ?

73.9 mL -- ?

Expert Solution

queen_honey_blossom answered 2 years ago

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