A 50.0 mL sample containing Cd2 and Mn2 was treated with 40.4 mL of 0.0500 M...

A 50.0 mL sample containing Cd2 and Mn2 was treated with 40.4 mL of 0.0500 M EDTA. Titration of the excess unreacted EDTA required 19.2 mL of 0.0300 M Ca2 . The Cd2 was displaced from EDTA by the addition of an excess of CN–. Titration of the newly freed EDTA required 18.2 mL of 0.0300 M Ca2 . What were the molarities of Cd2 and Mn2 in the original solution?

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queen_honey_blossom answered 1 year ago

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