In: Chemistry
Molar mass of H2 = 2.016 g/mol
mass(H2)= 5.35 kg = 5350 g
we have below equation to be used:
number of mol of H2,
n = mass of H2/molar mass of H2
=(5350.0 g)/(2.016 g/mol)
= 2.654*10^3 mol
Molar mass of N2 = 28.02 g/mol
mass(N2)= 31.8 Kg = 31800 g
we have below equation to be used:
number of mol of N2,
n = mass of N2/molar mass of N2
=(31800.0 g)/(28.02 g/mol)
= 1.135*10^3 mol
we have the Balanced chemical equation as:
3 H2 + N2 ---> 2 NH3
3 mol of H2 reacts with 1 mol of N2
for 2653.7698 mol of H2, 884.5899 mol of N2 is required
But we have 1134.9036 mol of N2
so, H2 is limiting reagent
we will use H2 in further calculation
Molar mass of NH3 = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
From balanced chemical reaction, we see that
when 3 mol of H2 reacts, 2 mol of NH3 is formed
mol of NH3 formed = (2/3)* moles of H2
= (2/3)*2653.7698
= 1.769*10^3 mol
we have below equation to be used:
mass of NH3 = number of mol * molar mass
= 1.769*10^3*17.03
= 3.01*10^4 g
= 30.1 Kg
Answer: 30.1 Kg