Consider the chemical equation 2NH3 ? N2 + 3H2. the equilibrium is to be established in...

Consider the chemical equation 2NH3 ? N2 + 3H2. the equilibrium is to be established in a 1 liter container at 1,000 K, where Kc= 4.0*^-2. Initially1,220 moles of NH3 are present. Estimate equilibrium concentration of H2.

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Expert Solution

Solution

Given data

Kc =4.0*10^-2

Initial moles of NH3 = 1220

Equilibrium concentration of H2= ?

Lets make the ICE table

2NH3 ------ > N2 + 3H2

I 1220 M 0 0

C -2x +x +3x

E 1220-x x 3x

Lets write the equilibrium constant expression

Kc =[N2][H2]³/[NH3]²

Now lets out the values in the formula

4.0*10^-2 = [x][3x]³/[1220-2x]²

4.0*10^-2 *[1220-2x]²=[x][3x]³

By solving this equation we get

X= 1.16

Therefore the equilibrium concentration of H2 = 3x = 3*1.16 = 3.48 M

queen_honey_blossom answered 4 months ago

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