Question
In: Statistics and Probability
The national distribution of fatal work injuries in a country is shown in the table to...
The national distribution of fatal work injuries in a country is
shown in the table to the right under
National %. You believe that the distribution of fatal work
injuries is different in the western part of the
country and randomly select 5000 fatal work injuries occurring in
that region. At
α= 0.10, can you conclude that the distribution of fatal work
injuries in the west is different from the
national distribution?
% Actual counts
Category 1 20% 1020
Category 2 30% 1505
Category 3 40% 2100
Category 4 10% 375
Solutions
Expert Solution
H0: Null Hypothesis: The distribution of fatal work injuries in the west is not different from the national distribution
HA:Alternative Hypothesis: The distribution of fatal work injuries in the west is different from the national distribution (Claim)
Test Statistic (
)
is got as follows:
| Category | Observed (O) | Expected (E) | (O - E)2/E |
| Category 1 | 1020 | 5000 X 0.20= 1000 | 0.400 |
| Category 2 | 1505 | 5000 X 0.30 = 1500 | 0.017 |
| Category 3 | 2100 | 5000 X 0.40 = 2000 | 5.000 |
| Category 4 | 375 | 5000 X 0.10 = 500 | 31.250 |
| Total =
= |
36.667 |
dt = 4 - 1 = 3
From Table, critical value of
=6.251
Since caluclated value of
= 36.667 is greater than critical value of
= 6.251. the difference is different. Reject null hypothesis.
Conclusion:
The data support the claim that the distribution of fatal work injuries in the west is different from the national distribution (Claim)
orchestra answered 2 years agoRelated Solutions
The national distribution of fatal work injuries in a country is shown in the table to...
The national distribution of fatal work injuries in a country is
shown in the table to the right under National %. You believe that
the distribution of fatal work injuries is different in the western
part of the country and randomly select 6231 fatal work injuries
occurring in that region. At alpha equals 0.05 can you conclude
that the distribution of fatal work injuries in the west is
different from the national distribution? Complete parts a through
d below. Cause...
The national distribution of fatal work injuries in a country is shown in the table to...
The national distribution of fatal work injuries in
a country is shown in the table to the right under National
%.
You believe that the distribution of fatal work injuries is
different in the western part of the country and randomly select
6231 fatal work injuries occurring in that region. At
alpha equals 0.10α=0.10
can you conclude that the distribution of fatal work injuries in
the west is different from the national distribution? Complete
parts a through d below.
calculate...
following data safety injury severity Fatal non-fatal no injuries total yes 669 155,071 467,362 623,102 no...
following data
safety injury severity
Fatal
non-fatal
no injuries
total
yes
669
155,071
467,362
623,102
no
487
4294
3824
8605
total
1,156
159,365
471,186
631,707
using this data, we wish to determine if there is any
association between using safety restraints and injury severity. as
such we will use a chi-square test for independence
Q10: state the null and alternative
hypotheses
Q11:fill in the table below with the expected counts
assuming the null hypothesis is true
safety restraint/injury severity
fatal...
How old are college students? The national age distribution for the youth is shown below. ...
How old are college students? The national age distribution for
the youth is shown below.
National Age Distribution for
the college
Age Under 26 26–35 36–45 46–55 Over 55 Percentage 39% 25% 16% 12%
8%
The Mountain Colleges took a random sample of 212 students and
obtained the following sample distribution.
Sample Distribution, Mountain
Colleges
Age Under 26 26–35 36–45 46–55 Over 55 Number of students 65 73 41
21 12 Is the sample age
distribution for the ...
Activity 1: National records have shown that the distribution of time lengths (in years) needed to...
Activity 1: National records have shown that the distribution
of time lengths (in years) needed to complete a bachelor's degree
is approximately bell-shaped (normal) where the mean is 4.6 yrs and
the standard deviation is .3 years.
1C. Would you expect someone to take more than 6 years to
complete a bachelor’s degree?
1D. What percent of college students take at most 4.3
years?
1E. What percent of college students take at least 5.2
years?
1F. What percent of students...
Table 2 below shows the national income accounting data for the year 2020 in Country A....
Table 2 below shows the national income accounting data for the
year 2020 in Country A. Using expenditure approach, calculate the
following values:
Items RM (Million)
Depreciation 560
Gross private domestic investment expenditures 5980
Imports 9900
Exports 3000
Federal government expenditures 7900
State and local government expenditures 1653
Personal consumption expenditure 8960
Transfer payments 300
Receipts of factor income from the rest of the world 930
Payments of factor income to the rest of the world 1890
(i) Gross domestic...
The joint probability distribution of random variables, X and Y, is shown in the following table:...
The joint probability distribution of random variables, X and Y,
is shown in the following table: X 2 4 6 Y 1 0.10 0.20 0.08 2 0.06
0.12 0.16 3 0.15 0.04 0.09
(a) Calculate P ( X=4 | Y=1)
(b) Calculate V (Y | X=2) .
(c) Calculate V (3Y-X ) .
Consider the population described by the probability distribution shown in the table. The random variable x...
Consider the population described by the probability
distribution shown in the table. The random variable x is observed
twice. If these observations are independent, all the different
samples of size 2 and their probabilities are shown in the
accompanying table. Complete parts a through
e below.
x
1
2
3
4
5
p(x)
0.4
0.1
0.2
0.2
0.1
x (bar over x)
1.0
1.5
2.0
2.5
3
3.5
4
4.5
5
p(x) (bar over x)
0.16
0.08
0.17
0.2
0.16...
The joint probability distribution of variables X and Y is shown in the table below. ...............................................................................X..........................................................................
The joint probability distribution of variables X and
Y is shown in the table below.
...............................................................................X.......................................................................
Y
1
2
3
1
0.30
0.18
0.12
2
0.15
0.09
0.06
3
0.05
0.03
0.02
Calculate E(XY)
Determine the marginal probability distributions of X
and Y.
Calculate E(X) and E(Y)
Calculate V(X) and V(Y)
Are X and Y independent? Explain.
Find P(Y = 2| X = 1)
Calculate COV(X,Y). Did you expect
this answer? Why?
Find the probability distribution...
The frequency distribution shown in the following table lists the number of hours per day a...
The frequency distribution shown in the following table lists
the number of hours per day a randomly selected sample of teenagers
spent watching television. Where possible, determine what percent
of the teenagers spent the following number of hours watching
television. (Round your answers to one decimal place. If not
possible, enter IMPOSSIBLE.)
Hours per day
Number
of
Teenagers
0 ≤
x < 1
17
1 ≤
x < 2
31
2 ≤
x < 3
24
3 ≤
x <...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Froya Fabrikker A/S of Bergen, Norway, is a small company that manufactures specialty heavy equipment for...
- When the electricity goes out on your campus, a backup source powers the servers that handle...
- I am having trouble with my assignment and getting compile errors on the following code. The...
- Can someone show me how to write a Haskell function using snd on a list of...
- Please do in java Program 3: Give a baby $5,000! Did you know that, over the...
- This is all one question, thank you so much in advance! You must evaluate the purchase...
- 10. Consider a market in which there is a monopoly manufacturer and a mo nopoly retailer....
ADVERTISEMENT