Question

In: Chemistry

You need to determine the concentration of a sulfuric acid solution by titration with a standard...

You need to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. You have a 0.1689 M standard solution. You take a 25.00 mL sample of the original acid solution and dilute it to 250.0 mL. You then take a 10.00 mL sample of the dilute acid solution and titrate it with the standard solution. You need 17.49 mL of the standard solution to reach the endpoint. What is the concentration of the original acid solution?

Solutions

Expert Solution

The reaction between H2SO4 and NaOH is as follows

That means to react one mole of H2SO4 we need 2 Mole of NaOH.

The formula for this type of titration problem is

V1M1   = V2M2

N1            N2               

Here                  V1 Volume of NaOH = 17.49 mL

                         M1 Molarity of NaOH = 0.1689 M

             N1 Number of moles of NaOH = 2

                       V2 Volume of H2SO4 = 10 mL

                     M2 Molarity of H2SO4 = x to be calculated

             N2 Number of moles of H2SO4 = 1

By substituting the above values in the above equation get

               17.49X0.1689       =       10X x

                     2                                 1

17.49X0.1689 =10 X x X 2

Molarity of H2SO4 x = 17.49X0.1689    =0.1477 M

                                          2X10

How ever this is not that original solution it is 10 times (25 mL of H2SO4 is diluted to 250 mL) diluted solution of original H2SO4 Solution

So the original H2SO4 solution morality 10 times of diluted solution = 0.1477X10 = 1.477 M


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