In: Chemistry
What is the molar concentration of a solution of sulfuric acid, H2SO4, if 8.09 mL react completely with 0.606 g of NaOH which was dissolved in 200 mL of water?
2NaOH + H2SO4 ----------------> Na2So4 + 2H2O
no of moles of NaOH = W/G.M.Wt
= 0.606/40 = 0.0152 moles
2 moles of NaOH react with 1 moles of H2SO4
0.0152 moles of NaOH react with = 1*0.0152/2 = 0.0076 moles of H2So4
molarity of H2SO4 = no of moles /volume in L
= 0.0076/0.00809 = 0.94 M
total volume of solution = 8.09+200 = 208.09ml
molarity of H2So4 in total volume of solution = 0.0076/0.20809 = 0.0365M