In: Chemistry
The reactant that determines how much of the products are made, is known as limiting reagent The other reactants are referred to as being in excess reagent.
For example
If 120 mg Benzaldehyde reacts with 0.56 ml of 3M CH3MgBr and produces 1-phenylethanol, Benzaldehyde is a limiting reagent and it determines how much 1-phenylethanol will be made.
To know, which reactant is a limiting reagent, calculate the moles of reactant. The reactant with least moles is a limiting reagent.
Write the reaction equation
PhCHO + CH3MgBr --------> PhCHOHCH3 + Mg2+ + Br-
Given- PhCHO = 120 mg
CH3MgBr = 0.56 ml
Step1: Calculate moles of Benzaldehyde
Mass of Benzaldehyde = 120 mg = 0.12 g
Molar mass of Benzaldehyde = 106.121 g/mol
Moles of Benzaldehyde = 0.12 g/106.121 g/mol = 0.00113 moles
Step2: Calculate moles of CH3MgBr
Volume of CH3MgBr = 0.56 ml
Molarity of CH3MgBr = 3M
Moles of CH3MgBr = C x V (L)
= 3 x (0.56/1000) = 0.00168 moles
Moles of benzaldehyde are less than moles of CH3MgBr, so benzaldehyde is limiting reagent.