In: Chemistry
The degree of dissociation, α, for the following reaction:
N2O4(g) <--> 2NO2(g)
is 0.655 at 298 K and 1.00 bar total pressure. Find K.
Ans------ given reaction is
N2O4(g) <--> 2NO2(g) let a be the initial concentration
and be the degree of
dissociation
initially a 0
at equilibrium a- a 2a
total number of mole = a- a +2a
=a(1+)
now, PN2O4=a- a/a(1+
)*P=1-
/1+
SinceP=1
PNO2=2a/a(1+
)*P=2
/1+
Now, K=(PNO2)2/(PN204)
K= 42/1-
2
k= 4(0.655)2/1-(0.655)2
k=3