Question

The degree of dissociation, α, for the following reaction:

N₂O_4(g) <--> 2NO_2(g)

is 0.655 at 298 K and 1.00 bar total pressure. Find K.

Answer 1

Ans------ given reaction is

N2O4(g) <--> 2NO2(g) let a be the initial concentration and be the degree of dissociation

initially a 0

at equilibrium a- a 2a

total number of mole =  a- a +2a

=a(1+)

now, P_N2O4=a- a/a(1+)*P=1-/1+ SinceP=1

PNO2=2a/a(1+)*P=2/1+

Now, K=(P_NO2)2/(P_N204)

K= 42/1-2

k= 4(0.655)2/1-(0.655)2

k=3