Question

In: Statistics and Probability

48 sample - 9 "0s" = 39 39 "1s" / 48 total sample= 0.8125 pq=0.9*(1-0.9) 0.09...

48 sample - 9 "0s" = 39

39 "1s" / 48 total sample=

0.8125

pq=0.9*(1-0.9)

0.09

pq/n= 0.09/48

0.001875

sqrt (pq/n)= sqrt (0.001875)

0.043301

sample prop / 90% =0.8125-0.9

-0.0875

z=-0.0875/0.043301

-2.02073

p value =NORMSDIST(H7)

0.02165

An air quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of air quality values. Second, at alpha=0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.

Time

Air Quality

0:00:00

1

0:00:30

1

0:01:00

1

0:01:30

1

0:02:00

1

0:02:30

1

0:03:00

1

0:03:30

1

0:04:00

1

0:04:30

1

0:05:00

1

0:05:30

1

0:06:00

1

0:06:30

1

0:07:00

1

0:07:30

1

0:08:00

1

0:08:30

0 (1)

0:09:00

0 (2)

0:09:30

0 (3)

0:10:00

1

0:10:30

1

0:11:00

1

0:11:30

0 (4)

0:12:00

1

0:12:30

0 (5)

0:13:00

1

0:13:30

0 (6)

0:14:00

1

0:14:30

1

0:15:00

0 (7)

0:15:30

1

0:16:00

0 (8)

0:16:30

1

0:17:00

1

0:17:30

0 (9)

0:18:00

1

0:18:30

1

0:19:00

1

0:19:30

1

0:20:00

1

0:20:30

1

0:21:00

1

0:21:30

1

0:22:00

1

0:22:30

1

0:23:00

1

0:23:30

1

Solutions

Expert Solution

Result:

An air quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of air quality values. Second, at alpha=0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.

Ho: P ≥ 0.9, H1: P < 0.9

This is a lower tail test.

single proportion test used.

calculated z = -2.0207

P=0.0217

Calculated P= 0.0217 < 0.10 level of significance.

The null hypothesis is rejected.

There is enough evidence to reject the claim that that proportion of times that air quality meets standards is at least 90%.

Z Test of Hypothesis for the Proportion

Data

Null Hypothesis            p =

0.9

Level of Significance

0.1

Number of Items of Interest

39

Sample Size

48

Intermediate Calculations

Sample Proportion

0.8125

Standard Error

0.0433

Z Test Statistic

-2.0207

Lower-Tail Test

Lower Critical Value

-1.2816

p-Value

0.0217

Reject the null hypothesis


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