In: Statistics and Probability
| 
 48 sample - 9 "0s" = 39  | 
 39 "1s" / 48 total sample=  | 
 0.8125  | 
| 
 pq=0.9*(1-0.9)  | 
 0.09  | 
|
| 
 pq/n= 0.09/48  | 
 0.001875  | 
|
| 
 sqrt (pq/n)= sqrt (0.001875)  | 
 0.043301  | 
|
| 
 sample prop / 90% =0.8125-0.9  | 
 -0.0875  | 
|
| 
 z=-0.0875/0.043301  | 
 -2.02073  | 
|
| 
 p value =NORMSDIST(H7)  | 
 0.02165  | 
An air quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of air quality values. Second, at alpha=0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.
| 
 Time  | 
 Air Quality  | 
| 
 0:00:00  | 
 1  | 
| 
 0:00:30  | 
 1  | 
| 
 0:01:00  | 
 1  | 
| 
 0:01:30  | 
 1  | 
| 
 0:02:00  | 
 1  | 
| 
 0:02:30  | 
 1  | 
| 
 0:03:00  | 
 1  | 
| 
 0:03:30  | 
 1  | 
| 
 0:04:00  | 
 1  | 
| 
 0:04:30  | 
 1  | 
| 
 0:05:00  | 
 1  | 
| 
 0:05:30  | 
 1  | 
| 
 0:06:00  | 
 1  | 
| 
 0:06:30  | 
 1  | 
| 
 0:07:00  | 
 1  | 
| 
 0:07:30  | 
 1  | 
| 
 0:08:00  | 
 1  | 
| 
 0:08:30  | 
 0 (1)  | 
| 
 0:09:00  | 
 0 (2)  | 
| 
 0:09:30  | 
 0 (3)  | 
| 
 0:10:00  | 
 1  | 
| 
 0:10:30  | 
 1  | 
| 
 0:11:00  | 
 1  | 
| 
 0:11:30  | 
 0 (4)  | 
| 
 0:12:00  | 
 1  | 
| 
 0:12:30  | 
 0 (5)  | 
| 
 0:13:00  | 
 1  | 
| 
 0:13:30  | 
 0 (6)  | 
| 
 0:14:00  | 
 1  | 
| 
 0:14:30  | 
 1  | 
| 
 0:15:00  | 
 0 (7)  | 
| 
 0:15:30  | 
 1  | 
| 
 0:16:00  | 
 0 (8)  | 
| 
 0:16:30  | 
 1  | 
| 
 0:17:00  | 
 1  | 
| 
 0:17:30  | 
 0 (9)  | 
| 
 0:18:00  | 
 1  | 
| 
 0:18:30  | 
 1  | 
| 
 0:19:00  | 
 1  | 
| 
 0:19:30  | 
 1  | 
| 
 0:20:00  | 
 1  | 
| 
 0:20:30  | 
 1  | 
| 
 0:21:00  | 
 1  | 
| 
 0:21:30  | 
 1  | 
| 
 0:22:00  | 
 1  | 
| 
 0:22:30  | 
 1  | 
| 
 0:23:00  | 
 1  | 
| 
 0:23:30  | 
 1  | 
Result:
An air quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of air quality values. Second, at alpha=0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%.
Ho: P ≥ 0.9, H1: P < 0.9
This is a lower tail test.
single proportion test used.

calculated z = -2.0207
P=0.0217
Calculated P= 0.0217 < 0.10 level of significance.
The null hypothesis is rejected.
There is enough evidence to reject the claim that that proportion of times that air quality meets standards is at least 90%.
| 
 Z Test of Hypothesis for the Proportion  | 
|
| 
 Data  | 
|
| 
 Null Hypothesis p =  | 
 0.9  | 
| 
 Level of Significance  | 
 0.1  | 
| 
 Number of Items of Interest  | 
 39  | 
| 
 Sample Size  | 
 48  | 
| 
 Intermediate Calculations  | 
|
| 
 Sample Proportion  | 
 0.8125  | 
| 
 Standard Error  | 
 0.0433  | 
| 
 Z Test Statistic  | 
 -2.0207  | 
| 
 Lower-Tail Test  | 
|
| 
 Lower Critical Value  | 
 -1.2816  | 
| 
 p-Value  | 
 0.0217  | 
| 
 Reject the null hypothesis  |