A 0.120-L sample of an unknown HNO3 solution required 29.1 mL of 0.200 M Ba(OH)2 for...

A 0.120-L sample of an unknown HNO3 solution required 29.1 mL of 0.200 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?

Expert Solution

Given Molarity of Ba(OH)₂ = 0.200 M

Volume of Ba(OH)₂ = 29.1 mL = 0.0291 L Sice 1 L = 1000 mL

So number of moles of Ba(OH)₂ is n = Molarity x volume in L

= 0.200 M x 0.0291 L

= 0.00582 mol

Ba(OH)₂ + 2HNO₃ Ba(NO₃)₂ + 2H₂O

According to the balanced equation ,

1 mole of Ba(OH)₂ reacts with 2 moles of HNO₃

0.00582 mole of Ba(OH)₂ reacts with 2x0.00582 = 0.01164 moles of HNO₃

So molarity of HNO₃ is ,

So the concentration of HNO₃ is 0.097 M

queen_honey_blossom answered 7 months ago

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