In: Chemistry
2 HNO3(aq) + Ca(OH)2(aq) → Ca(NO3)2(aq) + 2 H2O(l)
A 350 mL sample of 0.276 M HNO3 is partially neutralized by 125 mL of 0.120 M Ca(OH)2. Find the concentration of H+ (aq) in the resulting solution.
A. 0.210 M
B. 0.00632 M
C. 0.203 M
D. 0.0240 M
E. 0.140 M
narmality of HNO3 = n * molarity
= 1*0.276 = 0.276N
normality of Ca(OH)2 = 2*molarity
= 2*0.12 = 0.24N
2 HNO3(aq) + Ca(OH)2(aq) → Ca(NO3)2(aq) + 2 H2O(l)
HNO3 Ca(OH)2
NA = 0.276N NB = 0.24N
VA = 350ml VB = 125ml
N = NAVA-NBVB/VA+VB
= 0.276*350-0.24*125/350+125
= 66.6/475 = 0.14 N
N = [H+] = 0.14N = 0.14M
E. 0.140 M >>>>answer