In: Chemistry
Part B - Calculate the molar solubility in NaOH Based on the given value of the Ksp, what is the molar solubility of Mg(OH)2 in 0.180 M NaOH? Express your answer with the appropriate units. Hints
NaOH -------------> Na^+ (aq) + OH^-
0.18M 0.18M
Mg(OH)2 --------------------> Mg^2+ (aq) + 2OH^-
s 2s+0.18
[OH^-] = 2s + 0.18 = 0.18M [2s <<<<<0.18M]
Ksp = [Mg^2+][OH^-]^2
5.6*10^-11 = s*(0.18)^2
s = 1.73*10^-9
solubilit of Mg(OH)2 is 1.73*10^-9 M