The molar solubility of Cu3PO4 is 1.59 ⋅ 10^− 3 M. Calculate the solubility of each...

The molar solubility of Cu3PO4 is 1.59 ⋅ 10^− 3 M. Calculate the solubility of each ion in a saturated solution:

Expert Solution

The dissolution of PbCrO4(s) in aqueous solution takes place according to the following equation

Cu3PO4(s) + H2O(aq) <-----------> 3Cu+(aq) + PO43-(aq)

The solubility product constant of the above reaction is given by

Ksp = [3s]^3 [PO43-] = 1.59*10^-3
Ksp = s*(3s)^3 = 1.59*10^-3

s = 0.088 M or 0.088 moles/liter.

The molar solubility of Cu+ ion = 3*0.088 = 0.264 moles/liter.

The molar solubility of PO43 ion = 0.088 moles/liter.

queen_honey_blossom answered 2 years ago

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