Question

In: Chemistry

Use the following data to work through problems 4-6. 50.0 mL of each solution was used...

Use the following data to work through problems 4-6.

  • 50.0 mL of each solution was used in each experiment.
  • Each solution had a molarity of 2.00 M.
  • The density of the solutions once mixed are 1.03 g/mL.
  • The following table is data collected from an actual experiment.

Initial Temp

Final Temp

Temp Change

NaOH + HCL

19.85

33.07

13.2

NaOH+ NH4Cl

19.78

20.40

0.62

HCl + NH3

20.16

32.05

11.89

  1. Calculate the amount of heat energy, qsurroundings, produced in each reaction. Use 03 g/mL for the density of all solutions. Use the specific heat of water, 4.184 J/(g•°C), for each of the three reactions. qsurroundings = Cs ´ m ´ ∆T
  1. Calculate the enthalpy change, ∆Hreaction, per mole of reactant for each of the three reactions in units of kJ/mole.

                                    ∆Hreaction = ∆Hsystem

  1. Calculate a percent error between the accepted values for ∆Hreaction(use values calculated in question 1 as accepted values) and the “experimental” values you calculated in question 5 for each reaction.

                                               

                        % Error = Experimental – Accepted x 100

                                                Accepted

Solutions

Expert Solution

In this case, the volume, concentration and density conditions for each of the solutions will be considered the same. Therefore, the values of mass and moles are determined for each reaction:

To calculate the enthalpy of reaction:

For the calculation for each mole, then:

And so for each reaction, getting:

To calculate the percentage deviation, it is necessary to calculate the standard formation enthalpy with theoretical values, using the equation:

According to the exercise, the values have already been calculated previously. In any case, here are the theoretical formation values (Kj/mol) for each compound:

NaOH 469,4
HCl 92,31
NaCl 411
H2O 285,84
NH3 67,20
NH4Cl 315,4

For the reaction 1, so:

%

And so on:

As can be seen, the deviation percentages are very high. Remembering that it is perhaps necessary to perform a correction factor according to the ambient temperature, since the reaction enthalpies used are at a temperature of 25C. Or, verify the user values with the dice with the teacher and perform the same calculations again.


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