In: Chemistry
Consider how to prepare a buffer solution with pH =
3.19 (using one of the weak acid/conjugate base
systems shown here) by combining 1.00 L of a
0.435-M solution of weak acid with
0.358 M sodium
hydroxide.
Weak Acid | Conjugate Base | Ka | pKa |
---|---|---|---|
HNO2 |
NO2- |
4.5 x 10-4 |
3.35 |
HClO |
ClO- |
3.5 x 10-8 |
7.46 |
HCN |
CN- |
4.0 x 10-10 |
9.40 |
How many L of the sodium hydroxide solution would
have to be added to the acid solution of your choice?
Consider how to prepare a buffer solution with pH =
3.19 (using one of the weak acid/conjugate base
systems shown here) by combining 1.00 L of a
0.435-M solution of weak acid with
0.358 M sodium hydroxide.
total moles of acid = 1 x 0.435 = 0.435 mol
pH = 3.19
pKa = 3.35
HNO2 + NaOH ---------------> NO2- + H2O
0.435 0.358V 0 0
0.435-0.358V 0 0.358V
pH = pKa + log [NO2- / HNO2]
3.19 = 3.35 + log [0.358 V / 0.435 - 0.358 V]
[0.358 V / 0.435 - 0.358 V] = 0.6918
0.358 V = 0.30095 - 0.2477 V
V = 0.5 L
volume of sodium hydroxide = 0.500 L